Asked by maath

Find the length of the curve

y = x^2 - (1/8)lnx, 1 ≤ x ≤ e

Answers

Answered by oobleck
∫[1,e] √(1 + (2x - 1/(8x)))^2 dx
Answered by maath
how would you simplify that to a fraction
Answered by Bosnian
In google paste:

Find the length of the curve calculator

When you see list of results click on:

Arc Length Calculator for Curve - eMathHelp

When page be open in rectangle

Enter a function

paste:

x^2 - (1/8)lnx

Enter a lower limit: 1

Enter an upper limit: e

click on CALCULATE and follow steps

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