Asked by rebel
                I am an even, 3 digit palindrome. (ex. 464).  The product of the digits is 8.  What number am I?
            
            
        Answers
                    Answered by
            rebel
            
     i found it. the answer is 222
    
                    Answered by
            Bosnian
            
    If write your number as:
a b a
The product is:
a ∙ b ∙ a = a² ∙ b = 8
The factors of 8 are:
1, 2, 4, 8
a² and b could be any of the factors listed.
But in your task a² ∙ b = 8, so a² can be only 1 and 2 becouse:
for a = 4 the product is greater of 4², greater of 16
for a = 8 the product is greater of 8², greater of 64
So the solutions are 181 and 222
    
a b a
The product is:
a ∙ b ∙ a = a² ∙ b = 8
The factors of 8 are:
1, 2, 4, 8
a² and b could be any of the factors listed.
But in your task a² ∙ b = 8, so a² can be only 1 and 2 becouse:
for a = 4 the product is greater of 4², greater of 16
for a = 8 the product is greater of 8², greater of 64
So the solutions are 181 and 222
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