Asked by william
The amount of copper was determined in 10 g sample. copper was precipitated, filtered and calcined, obtaining a final precipitate of 0.79 g oxide of copper , What % in copper mass in this sample?
Answers
Answered by
DrBob222
Your post isn't complete. You don't say if the oxide is CuO or Cu2O. At lower temperatures (200-400 C) the product is CuO but at higher temperature (say1000 C) is Cu2O. I will assume the product is CuO and you can make the change if that is necessary.
0.79 g CuO x (atomic mass Cu/molar mass CuO) = ? = mass Cu in the 10 g sample.
Then % Cu in sample = (grams Cu from above/10)*100 = ?
0.79 g CuO x (atomic mass Cu/molar mass CuO) = ? = mass Cu in the 10 g sample.
Then % Cu in sample = (grams Cu from above/10)*100 = ?
Answered by
william
Thank u , you save my life !!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.