Asked by scottpilgrim

What is the average rate of change for the function f(x) = x^3 − 6x^2 + 4x +7 over the interval 0≤x≤5?
Answered by oobleck
that is just the slope of the secant line over the interval:
(f(5)-f(0))/(5-0)
Answered by scottpilgrim
what's the rate of change though?
Answered by oobleck
it is the value of the expression I gave you. Surely by now you can plug in a value for x and calculate f(x) ? So, the average ate of change over the interval is
(5^3 − 6*5^2 + 4*5x +7)-(0^3 − 6*0^2 + 4*0 +7))/(5-0)

Looks like you need to review this section.
Answered by bleh
bruh i came here to cheat gimmi the answer
Answered by bray
the people on here that decide to give you another even longer equation than the answer are straight virgins : | no playin
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