Question

A 25 gram piece of metal is sitting in a beaker of boiling water. The metal is taken out of the beaker and quickly placed in a calorimeter that contains 85 mL of water at 25.0 degree Celcius. After the metal released all of its heat the temperature of the water is 27.5 degrees Celcius.
What is the specific heat of the metal?

Answer 1

heat = mass * specific heat * temperature change

25 * x * (100. - 27.5) = 85 * 4.19 j/g⋅ºC * (27.5 - 25.0)

Answer 2

WHAT IS THE SPECIFIC HEAT OF WATER? IS IT 4.184?

Answer 3

WHERE DOES 100 COMES FROM?

Answer 4

The 100 comes from the boiling water. Water boils at 100 degrees celsius, so we assume the initial temperature of the metal was 100 degrees celsius. Because change of Temp is final minus initial, we do 27.5 - 100.