a 100 gram sample of a metal undergoes a temperature change from 20 C to 50 C Absorbing 1500J of heat
2 answers
I don't see a question here.
If the problem asks for the specific heat capacity, then we just use the formula,
Q = mc(T2-T1)
where
Q = heat (J)
m = mass (g)
c = specific heat capacity (J/g-K)
T2 = final temperature (K)
T1 = initial temperature (K)
Substituting,
1500 = 100 * c * (50 - 20)
c = ?
Now solve for c. Hope this helps~ `u`
Q = mc(T2-T1)
where
Q = heat (J)
m = mass (g)
c = specific heat capacity (J/g-K)
T2 = final temperature (K)
T1 = initial temperature (K)
Substituting,
1500 = 100 * c * (50 - 20)
c = ?
Now solve for c. Hope this helps~ `u`
1 answer