Asked by JAMYANG
Three designs are proposed for an engine that is to operate between 500 and 300 K. Design A is claimed to produce 750 J of work per kilojoule of heat input, B is claimed to produce 500 J, and C is claimed to produce 250J. Which design would you choose?
Answers
Answered by
bobpursley
efficiency=(500-300)/300=.67
work output= 1000*eff=670 J
so the first design A is baloney
so go with design B would be my choice.
work output= 1000*eff=670 J
so the first design A is baloney
so go with design B would be my choice.
Answered by
JAMYANG
what formula did u use?
Answered by
Pa
Greetings!
Do you currently have someone who does your graphic design? If not, I am currently available to work remotely.
My main focus is logo design, social media graphics, cover photos, ad banners and promotions.
If you need me or want to see my work, please reach out: [email protected] ( I used a no-reply email in the form )
Best,
Paul D.
Graphic Designer
[email protected]
Do you currently have someone who does your graphic design? If not, I am currently available to work remotely.
My main focus is logo design, social media graphics, cover photos, ad banners and promotions.
If you need me or want to see my work, please reach out: [email protected] ( I used a no-reply email in the form )
Best,
Paul D.
Graphic Designer
[email protected]
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