Question

How many miles of vapor are formed when 10 liters of butane gas, C4H10 is burned in oxygen at STP?

Answers

Can't answer with just one dimension of miles. Perhaps you meant "moles"..
2C4H10 + 13O2 ==> 8CO2 + 10H2O
10 L C4H10 will give you 40 L CO2 vapor and 50 L H2O vapor.or a total of 90 L gas @ STP. 1 mol occupies 22.4L so convert 90 L to mols with the factory of 22.4 L.
2C4H10 +13H2O=8Co2 +10H2O
10\44.8=X\10
X=10×10\44.8
X=100\44.8
X=2.23
2C4H10 +13H2O=8Co2 +10H2O
10\44.8=X\10
X=10×10\44.8
X=100\44.8
X=2.23
i.e If the mile is mole

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