Asked by Helen
How many miles of vapor are formed when 10 liters of butane gas, C4H10 is burned in oxygen at STP?
Answers
Answered by
DrBob222
Can't answer with just one dimension of miles. Perhaps you meant "moles"..
2C4H10 + 13O2 ==> 8CO2 + 10H2O
10 L C4H10 will give you 40 L CO2 vapor and 50 L H2O vapor.or a total of 90 L gas @ STP. 1 mol occupies 22.4L so convert 90 L to mols with the factory of 22.4 L.
2C4H10 + 13O2 ==> 8CO2 + 10H2O
10 L C4H10 will give you 40 L CO2 vapor and 50 L H2O vapor.or a total of 90 L gas @ STP. 1 mol occupies 22.4L so convert 90 L to mols with the factory of 22.4 L.
Answered by
Beza
2C4H10 +13H2O=8Co2 +10H2O
10\44.8=X\10
X=10×10\44.8
X=100\44.8
X=2.23
10\44.8=X\10
X=10×10\44.8
X=100\44.8
X=2.23
Answered by
Beza
2C4H10 +13H2O=8Co2 +10H2O
10\44.8=X\10
X=10×10\44.8
X=100\44.8
X=2.23
i.e If the mile is mole
10\44.8=X\10
X=10×10\44.8
X=100\44.8
X=2.23
i.e If the mile is mole
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