Question
What is the vapor pressure of a solution of 0.5mol of a non-volatile impurity x and 2.0 g of TaCl5 (L) at a temperature of 226 degrees celcius? The vapor pressure of TaCl5 (l) at 226 degrees celcius ,621mmHg
Answers
DrBob222
Note the correct spelling of celsius.
n x = 0.5
mol TaCl5 = grams/molar mass
Xx = nx/total mols
XTaCl5 = nTaCl5/total mols.
pTaCl5 = Xx*PoTaCl5
n x = 0.5
mol TaCl5 = grams/molar mass
Xx = nx/total mols
XTaCl5 = nTaCl5/total mols.
pTaCl5 = Xx*PoTaCl5