Asked by stefani
What is the vapor pressure (in torr) of a solution comprised of 220 g of ethanol (C₂H₅OH) in 870 g of H₂O at 25 °C where H₂O has a pressure of 23.76 torr?
Answers
Answered by
DrBob222
mols H2O = 870/18 = about 48
mols EtOH = 220/46 = about 5 but these abouts are just estimates. You should redo these two and all calculations that follow.
total mols = 53 and
XEtOH = mols EtOH/total mols = about 5/53 = about 0.1
XH2O = about 48/53 = about 0.9
Then Psoln = XH2O x P<sup>o</sup><sub>H2O
about 0.9 x 23.76 = ?
mols EtOH = 220/46 = about 5 but these abouts are just estimates. You should redo these two and all calculations that follow.
total mols = 53 and
XEtOH = mols EtOH/total mols = about 5/53 = about 0.1
XH2O = about 48/53 = about 0.9
Then Psoln = XH2O x P<sup>o</sup><sub>H2O
about 0.9 x 23.76 = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.