Asked by kyle

What is the vapor pressure (in mm Hg) of a solution of 12.5 g of glucose ( C6H12O6) in 75.0 g of methanol (CH3OH) at 27 degrees celcius? The vapor pressure of pure methanol at 27 degrees celcius is 140 mm Hg.
Answered by DrBob222
moles glucose = grams/molar mass.
moles methanol = grams/molar mass.
X<sub>methanol</sub> = moles CH3OH/total moles.

Psoln = Xmethanol*P<sup>o</sup><sub>methanol</sub>.
Answered by Dpontz
134.728 mm Hg
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