Asked by iratze
A hiker leaves for camp and walked 3.5 KM in a direction of 55 south of West to the lake. After a short rest at the lake she has 2.7 KM in a direction of 16 used to sell to the scenic overlook
Answers
Answered by
Damon
Huh?
Answered by
oobleck
so she ends up z km from camp, where
z^2 = 3.5^2 + 2.7^2 - 2(3.5)(2.7) cos(55-16)°
z = 2.2 km
z^2 = 3.5^2 + 2.7^2 - 2(3.5)(2.7) cos(55-16)°
z = 2.2 km
Answered by
oobleck
oops. I had her going S55W, rather than W55S.
z^2 = 3.5^2 + 2.7^2 - 2(3.5)(2.7) cos(25-16)°
z^2 = 3.5^2 + 2.7^2 - 2(3.5)(2.7) cos(25-16)°
Answered by
fred
5.6 Km
77 degrees south of west
77 degrees south of west
Answered by
Gigachad
Fred is correct :)
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