Question

I would be very grateful to have these answered with showing work
In order to produce a lead (II) chromate precipitate, lead (II) chloride reacts with sodium chromate in solution. A 12.5 g mass of lead (II) chloride is mixed into solution, and is allowed to react with excess sodium chromate.
a) what is the predicted yield of lead (II) chromate?
b) calculate the percentage yield if 13.8 g of lead (II) chromate is produced experimentally.

Answer 1

Well, you can start with
Na2CrO4 + Pb(NO3)2 -> PbCrO4 + NaNO3
Balance that equation, then convert the grams to moles to see what limits the reaction.

Answer 2

I should point out that PbCl2 is insoluble and normally one doesn't have solutions of lead(II) chloride.