Asked by Mr Jones
A body of mass 4.0 kg moving with a speed of 2.5 m/s collides with a stationary body of mass 0.2 kg. if the two bodies stick together after collision, calculate the magnitude of the velocity with which they move.?
Answers
Answered by
oobleck
conserve momentum.
4.0*2.5 + 0.2*0 = (4.0+0.2)*v
4.0*2.5 + 0.2*0 = (4.0+0.2)*v
Answered by
henry2,
Given: M1 = 4kg, V1 = 2.5m/s.
M2 = 0.2kg, V2 = 0.
V3 = velocity of M1 and M2 after collision.
Momentum before = Momentum after.
M1*V1+M2*V2 = M 1*V3+M2*V3
4*2.5+0.2*0 = 4V3+0.2V3
4.2V3 = 10
V3 = 2.4 m/s.
M2 = 0.2kg, V2 = 0.
V3 = velocity of M1 and M2 after collision.
Momentum before = Momentum after.
M1*V1+M2*V2 = M 1*V3+M2*V3
4*2.5+0.2*0 = 4V3+0.2V3
4.2V3 = 10
V3 = 2.4 m/s.
Answered by
George Cole jr
A body of mass 4.0kg move with a velocity of 6m/s calculate the momentum of the body
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