625 = w^2 + (3w+3)^2 = w^2 + 9(w+1)^2 = w^2+9w^2+18w+9
625 = 10 w^2 + 18 w + 9
10 w^2 + 18 w - 616 = 0
5 w^2 + 9 w - 308 = 0
https://www.mathsisfun.com/quadratic-equation-solver.html
w = 7 (or - 8.8 :)
L = 21 + 3
If the diagonal of a rectangle is 25 cm and the length is 3cm more than triple the width what are the dimensions
3 answers
width --- x
length -- 3x + 3
x^2 + (3x+3)^2 = 25^2
x^2 + 9x^2 + 18x + 9 - 625 = 0
10x^2 + 18x - 616 = 0
solve the quadratic using your favourite method
make sure to reject the negative and only use the positive answer
length -- 3x + 3
x^2 + (3x+3)^2 = 25^2
x^2 + 9x^2 + 18x + 9 - 625 = 0
10x^2 + 18x - 616 = 0
solve the quadratic using your favourite method
make sure to reject the negative and only use the positive answer
recognize the familiar 7-24-25 right triangle?