A tennis ball connected to a string is spun around in a vertical, circular path at a uniform speed. The ball has a mass m = 0.167 kg and moves at v = 4.9 m/s. The circular path has a radius of R = 0.98 m

Question

1.)What is the magnitude of the tension in the string when the ball is at the bottom of the circle?

2.)What is the magnitude of the tension in the string when the ball is at the side of the circle?

3.)What is the magnitude of the tension in the string when the ball is at the top of the circle?

Answer 1

the centripetal force (tension in the string)
... keeps the ball moving in a circle

the force necessary is ... m v^2 / r = .167 * 4.9^2 / .98 ... Newtons
... this is the tension at the sides of the circle

at the top and bottom of the circle
... the weight of the ball adds to or subtracts from the string tension

Answer 2

Where are the equations, worked with equations?