Asked by Mike
In triangle ABC, AB = BC. Calculate the angle a for ADC.
It is two triangles (A triangle within a triangle) and I'm trying to figure out the angles for them all.
Image link (I hope this is ok, I don't know how else to relay this): i.imgur.com/wKOva19.png
One angle is 31 degrees. Looking at the picture, if AB=BC then A and C must be 74.5 degrees. That totals 180 and should be right.
Now the issue is getting what getting the small a angle is. I assume I need to solve the left side first before the right side, but how does this work? I understand how to get the outer degree/etc but getting D or the split up A is confusing me.
It is two triangles (A triangle within a triangle) and I'm trying to figure out the angles for them all.
Image link (I hope this is ok, I don't know how else to relay this): i.imgur.com/wKOva19.png
One angle is 31 degrees. Looking at the picture, if AB=BC then A and C must be 74.5 degrees. That totals 180 and should be right.
Now the issue is getting what getting the small a angle is. I assume I need to solve the left side first before the right side, but how does this work? I understand how to get the outer degree/etc but getting D or the split up A is confusing me.
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