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The bearings of ships A andB from Port P are 225° and 116° respectively.Ship A is 3.9km from ship B on a bearing of 258°.Calcul...Asked by Emmanuel
The bearings of ships A AND B from port p are 2.25 degree and 116 respectively.ship A is 3.9km from ship B on a bearing of 258 degree. Calculate the distance of ship A from p
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Answered by
Emmanuel
sorry i haven't see how to solve or please draw for me.
Answered by
Reiny
Trying to follow your description, but I am not able to sketch the diagram.
Answered by
henry2,
Given: PA = ___ [225o], PB = ___ [116o], AB = 3.9km[258o], PA = ?.
P = 180-45-26 = 109o.
B = 90-64-12 = 14o.
A = 180-109-14 = 57o.
PA/sin14 = 3.9/sin109
PA = 1 km.
PA = 1km[225o].
PB/sin57 = 3.9/sin109
PB = 3.5 km.
PB = 3.5 km[116o].
P = 180-45-26 = 109o.
B = 90-64-12 = 14o.
A = 180-109-14 = 57o.
PA/sin14 = 3.9/sin109
PA = 1 km.
PA = 1km[225o].
PB/sin57 = 3.9/sin109
PB = 3.5 km.
PB = 3.5 km[116o].
Answered by
henry2,
Note: The 2.25o given by the student should have been 225o.
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