Question

The bearings of ships A andB from Port P are 225° and 116° respectively.Ship A is 3.9km from ship B on a bearing of 258°.Calculate the distance of ship A from P
Draw the triangle PAB
∡B = 38°
∡A = 33°
side p = 3.9
So, ∡P = 109°
Using the law of sines,
b/sin38° = 3.9/sin109°
b = 2.54 km
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