Question
Evaluate the following limits. If necessary, change the form of the function.
a) lim x -> 1 = (x^2 - 3x +5)/(x-2)
=(x^2 - 3x +5)/(x-2)
=(1^2 - (3(1)+5)/(1-2)
= -3
b) lim x-> 0 = (4x-5x^2)/x
=(4x-5x^2)/x
=x(4-5x)/x
=4-5x
=4-5(0)
=4
can someone see if my answers correct?
a) lim x -> 1 = (x^2 - 3x +5)/(x-2)
=(x^2 - 3x +5)/(x-2)
=(1^2 - (3(1)+5)/(1-2)
= -3
b) lim x-> 0 = (4x-5x^2)/x
=(4x-5x^2)/x
=x(4-5x)/x
=4-5x
=4-5(0)
=4
can someone see if my answers correct?
Answers
oobleck
a) your answer is correct, but you have an extra paren in lin e 3.
(1^2 - (3(1)+5)/(1-2)
should be
(1^2 - 3(1) + 5)/(1-2)
b) is also correct
(1^2 - (3(1)+5)/(1-2)
should be
(1^2 - 3(1) + 5)/(1-2)
b) is also correct