Asked by David

In the process of being thrown, a 0.500 kg ball travels at a speed of 10.0m/s over a distance of 0.75m. What is the force that was exerted on the ball?

Answered by henry2,
Work is the change in kinetic energy:
W = KE = 0.5M*V^2 = 0.5*0.5*10^2 = ___ Joules.
Answered by henry2,
F*d = 25
F*0.75 = 25
F = 33.3 N.
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