Asked by nikko
how do you write the equation: x^2+y^2+x+y-1/4=0 in standard form and factored form?
Answers
Answered by
Kenny
x^2+y^2+x+y-1/4=0
x²+y²+x+y=1/4
x²+(1/2)²+x+[y²+(1/2)²+y]=1/4+2(1/2)²
(x+1/2)²+(y+1/2)²=(1/4+1/2)
(x+1/2)²+(y+1/2)²-3/4=0
x²+y²+x+y=1/4
x²+(1/2)²+x+[y²+(1/2)²+y]=1/4+2(1/2)²
(x+1/2)²+(y+1/2)²=(1/4+1/2)
(x+1/2)²+(y+1/2)²-3/4=0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.