Asked by Corey
How do i write a equation of 8x+x^2-2y=64-y^2 ?
Answers
Answered by
Reiny
I recognize this to be an circle.
Do you want it in standard form?
if so, then ...
8x+x^2-2y=64-y^2
x^2 + 8x + ... + y^2 - 2y + ... = 64
complete the square
x^2 + 8x + 16 + y^2 - 2y + 1 = 64 + 16 + 1
(x + 4)^2 + (y-1)^2 = 81
centre is (-4,1), radius is 9
Do you want it in standard form?
if so, then ...
8x+x^2-2y=64-y^2
x^2 + 8x + ... + y^2 - 2y + ... = 64
complete the square
x^2 + 8x + 16 + y^2 - 2y + 1 = 64 + 16 + 1
(x + 4)^2 + (y-1)^2 = 81
centre is (-4,1), radius is 9
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.