Question
Your town's public library is building a new wheelchair ramp to its entrance. By law, the maximum angle of incline for the ramp is 4.76°. The ramp will have a vertical rise of 1.5 ft. What is the shortest horizontal distance that the ramp can span.
a) 11.5 ft.
b) 2.6 ft.
c) 7.1 ft.
d) 18.0 ft.
I'm not sure which is correct
a) 11.5 ft.
b) 2.6 ft.
c) 7.1 ft.
d) 18.0 ft.
I'm not sure which is correct
Answers
Did you draw it? Surely you know tangent = Opposite / adjacent
1. 11sqrt/3/3
2. -37x/9
3. 24.0ft
4. csctheta=sqrt5
5. cos4pi/3, sin7pi/6
6. f(x)=cos(x-pi/2)
7. f(x)=cosx
8. pi/4 units to the right
9. sqrt6-sqrt2/4
10. 73°
11. x=pi/6, pi/4, 3pi/4, 5pi/6
12. (sqrt10, 288.4°), (-sqrt10, 108.4°)
13. r=2/2-sintheta
14. 32sqrt3+32i
15. (-8, -4)
16. The vectors are not orthogonal. The angle between the two vectors is 101.3°
17. v+w=u for v=4i+3j, w=2i-j, and u=6i+2j
18. v=(180sqrt3-120sqrt2)i+(180+120sqrt2)j
19. u=sqrt5/5i-2sqrt5/5j
20. (-2, 0)
21. r=4cot theta csc theta
22. 7.43 seconds
23. x=t+5 y=4t^2-3t-18
24. r=4sin theta
25. 8
26. y=-11x-16
2. -37x/9
3. 24.0ft
4. csctheta=sqrt5
5. cos4pi/3, sin7pi/6
6. f(x)=cos(x-pi/2)
7. f(x)=cosx
8. pi/4 units to the right
9. sqrt6-sqrt2/4
10. 73°
11. x=pi/6, pi/4, 3pi/4, 5pi/6
12. (sqrt10, 288.4°), (-sqrt10, 108.4°)
13. r=2/2-sintheta
14. 32sqrt3+32i
15. (-8, -4)
16. The vectors are not orthogonal. The angle between the two vectors is 101.3°
17. v+w=u for v=4i+3j, w=2i-j, and u=6i+2j
18. v=(180sqrt3-120sqrt2)i+(180+120sqrt2)j
19. u=sqrt5/5i-2sqrt5/5j
20. (-2, 0)
21. r=4cot theta csc theta
22. 7.43 seconds
23. x=t+5 y=4t^2-3t-18
24. r=4sin theta
25. 8
26. y=-11x-16