Question

Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?
A. 4 • start fraction 2 superscript 3 baseline over 2 superscript 3 baseline end fraction
B. 2 • start fraction 2 superscript 3 baseline over 2 superscript 4 baseline end fraction
C. 3 • start fraction 2 superscript 3 baseline over 2 superscript 4 baseline end fraction
D. 3 • start fraction 2 superscript 4 baseline over 2 superscript 4 baseline end fraction

Answer 1

A. 4 * 2^3 over 2^3
B. 2 * 2^3 over 2^4
C. 3 * 2^3 over 2^4
D. 3 * 2^4 over 2^4

Answer 2

something divided by itself equals one

something multiplied by one equals itself

Answer 3

what is the answer

Answer 4

What’s the answer mine only gives me one choice

Answer 5

1. -9
2.y^19
3.w^-6
4.2^3/2^3
5.taylor changed the negative exponent to a negative base. the problem should be 2^-4 = 1/2^4= 1/2.2.2.2=1/16

Answer 6

Guys answers ;) is correct!! I got 100

Answer 7

thank youuuuuu:)

Answer 8

answers is correct!! thank you <33

Answer 9

Answer is correct!

Answer 10

Thank god i havent found any answers for math since eighth grade started i was worried

Answer 11

also tysm answers <3