Asked by stefani

If we electrolyze a solution of Ni²⁺(aq) to form Ni(s) and use a current of 0.15 amps for 10 minutes, how many grams of Ni(s) are produced?
Answered by oobleck
sigh
another homework dump...
Answered by DrBob222
To follow up on oobleck's observation, you posted about a dozen questions a few days ago in less than a minute. I posted answers to all of those although I saw no effort on your part. Today you've posted a dozen but it took you longer. I've not looked at all of them but the two I did I saw no effort on your part. Our goal on Jiskha is to HELP. This is not a homework dump site. Please go back and show us what you know on the other problems. Explain what you don't understand about the problem and where you need help and someone will gladly help you through what you don't understand. Here is how to proceed on this problem.
How many coulombs do you have? That's
C = amperes x seconds = 0.15 x 10 min x((60 s/min) = 90
It will take 96,485 coulombs to deposit 58.7/2 = 29.3 g Ni.
g Ni deposited = 29.3 g x (90/96,485) = ?
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