A journey of 700km partly by train and partly by bus. He started his journey at 8.00 a.m. by train which traveled at 50km/h. After alighting from the train, he took a lunch break of 30 minutes. He then continued his journey by bus which traveled at 75km/h. The whole journey took 11.5hours .

Question

Determine:

(a) the distance traveled by bus;
Time by train = (700-b)/50
Time by bus = b/75
(700 - b)/50 + b/75 = 11
50b + 52500 - 75b = 41250
- 25b + 52500 = 41250
-25b = 41250 - 52500
-25b = -11250
b = 450km

b) The bus developed a puncture after traveling 187.5km. It took 15 minutes to replace wheel. Find the time taken to complete the remaining part of the journey.

Answer 1

The first part of your solution is correct.

Since the puncture happened on the bus, and it happened after 187.5 km of the 450 km bus trip,
there were still 262.5 km to go,
at 75 km/h that would take
262.5/75 hours or 3.5 hours