Asked by Kd

A journey of 700km partly by train and partly by bus. He started his journey at 8.00 a.m. by train which traveled at 50km/h. After alighting from the train, he took a lunch break of 30 minutes. He then continued his journey by bus which traveled at 75km/h. The whole journey took 11.5;hours .

Determine:

(i) the distance traveled by bus;
Time by train = (700-b)/50
Time by bus = b/75

(700 - b)/50 + b/75 = 11
50b + 52500 - 75b = 41250

- 25b + 52500 = 41250

-25b = 41250 - 52500

-25b = -11250

b = 450km

(ii) the time Makau started traveling by bus.

450/75
= 6 hours

= 8.00 + 11.30
= 1930h

= 1930 - 0600

= 1330
= 1.30 p.m
b) The bus developed a puncture after traveling 187.5. It took 15 minutes to replace wheel. Find the time taken to complete the remaining part of the journey.
Answered by oobleck
again? come on
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