Asked by peter
                A 0.5000g sample of FeO is ignited to Fe2O3; what is the percentage gain in weight? 
            
            
        Answers
                    Answered by
            DrBob222
            
    Assuming no losses, the sample of Fe2O3 will have a mass of
0.5000 x (molar mass Fe2O3/2*molar mass FeO) = ?
Weight gain is the difference between ? and 0.5000 = let's say y.
Then % gain = 100y/0.5000 = ?
    
0.5000 x (molar mass Fe2O3/2*molar mass FeO) = ?
Weight gain is the difference between ? and 0.5000 = let's say y.
Then % gain = 100y/0.5000 = ?
                    Answered by
            DrBob222
            
    You must be a fairly good typist; you typed four (4) questions in less than a minute. Also I note you didn't send a lot of time telling how you thought the problems might be solved. 
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.