Asked by Emily
The lines y=(2/3)x+2 and y=(-2/3)x+12 are tangent to circle C at the points (3,4) and (3,10), respectively.
a) Find the coordinates of C and the radius of circle C. Explain your reasoning.
b)Write the standard equation of circle C.
a) Find the coordinates of C and the radius of circle C. Explain your reasoning.
b)Write the standard equation of circle C.
Answers
Answered by
oobleck
Two radii of the circle are the lines perpendicular to the given lines. They are
y = -3/2 (x-3)+4
y = 3/2 (x-3)+10
They intersect at the center of the circle: (1,7)
The radius of the circle is r^2 = (1-3)^2 + (7-4)^2 = 13
The circle is (x-1)^2 + (y-7)^2 = 13
y = -3/2 (x-3)+4
y = 3/2 (x-3)+10
They intersect at the center of the circle: (1,7)
The radius of the circle is r^2 = (1-3)^2 + (7-4)^2 = 13
The circle is (x-1)^2 + (y-7)^2 = 13
Answered by
Emily
Thanks for your response oobleck!
When finding radii equations, why did you say "(x-3)?"
When finding radii equations, why did you say "(x-3)?"
Answered by
oobleck
review the point-slope form of a line.
the line with slope m through (h,k) is
y-k = m(x-h)
the line with slope m through (h,k) is
y-k = m(x-h)
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