Asked by Rhy

A line segment has one endpoint of

A (2,5) and a slope of (2/3) find coordinates for B
Answered by Kenny
y-y1=m(x-x1)

y-5=2/3(x-2)

3y-15=2x-4

3Y-15=2x-4

3y=2x-11

Y=(2x-11)/3

When x=0 what is y=?

Which ever value you want for x just insert it and you would get a corresponding value
Answered by Reiny
y - 5 = (2/3)(x-2)
y = (2/3)(x-2) + 5

pick any value of x, then find y and you have a possible point for B
There are an infinite number of such points.
e.g. let x = 5, then y = (2/3)(3) + 5 = 7
B would be (5,7)
check: slope AB = (7-5)/(5-2) = 2/3 , looks good
Answered by henry2,
A(2, 5), B(x, y). m/= 2/3.
y-5 = 2, Y = 7.
x-2 = 3, X = 5.

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