Asked by Shiro
In a titration experiment, 20.4 mL of 0.883 M π»πΆπππ» neutralize 19.3 mL of π΅π(ππ»)2. What is the concentration of the π΅π(ππ»)2 solution?
Do I use M1V1=M2V2? my answer is 0.467, is this correct?
Do I use M1V1=M2V2? my answer is 0.467, is this correct?
Answers
Answered by
DrBob222
No. You do not use M1V1 = M2V2. That formula works very well for titrations that are 1:1; i.e., say NH3 + HCl ==> NH4Cl. It does NOT work for reactions that are not 1:1: i.e., 2HCOOH + Ba(OH)2 ==> Ba(OOCH)2.
By the way I worked this problem for you yesterday. The answer to day is the same. I will try to find it and post it with a link for you.
By the way I worked this problem for you yesterday. The answer to day is the same. I will try to find it and post it with a link for you.
Answered by
DrBob222
Here is my work on the problem yesterday.
https://www.jiskha.com/questions/1823891/in-a-titration-experiment-20-4-ml-of-0-883-m-neutralize-19-3-ml-of
https://www.jiskha.com/questions/1823891/in-a-titration-experiment-20-4-ml-of-0-883-m-neutralize-19-3-ml-of
Answered by
Shiro
Ohhh, sorry i already forgot that i already ask the question, i thought no one answer the previous one so i asked it again. thank you dr bob,
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.