Asked by Shiro
In a titration experiment, 20.4 mL of 0.883 M π»πΆπππ» neutralize 19.3 mL of π΅π(ππ»)2. What is the concentration of the π΅π(ππ»)2 solution?
Answers
Answered by
DrBob222
2HCOOH + Ba(OH)2 ==> Ba(OOCH)2 + 2H2O
mols HCOOH = M x L = ?
Looking at the balanced equation,mols Ba(OH)2 is 1/2 mols HCOOH.\
Then M Ba(OH)2 = mols BaOH)2/L Ba(OH)2 = ?
mols HCOOH = M x L = ?
Looking at the balanced equation,mols Ba(OH)2 is 1/2 mols HCOOH.\
Then M Ba(OH)2 = mols BaOH)2/L Ba(OH)2 = ?
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