Question

In a titration experiment, 20.4 mL of 0.883 M 𝐻𝐢𝑂𝑂𝐻 neutralize 19.3 mL of π΅π‘Ž(𝑂𝐻)2. What is the concentration of the π΅π‘Ž(𝑂𝐻)2 solution?

Answers

DrBob222
2HCOOH + Ba(OH)2 ==> Ba(OOCH)2 + 2H2O
mols HCOOH = M x L = ?
Looking at the balanced equation,mols Ba(OH)2 is 1/2 mols HCOOH.\
Then M Ba(OH)2 = mols BaOH)2/L Ba(OH)2 = ?

Related Questions