Asked by Shiro
                In a titration experiment, 20.4 mL of 0.883 M π»πΆπππ» neutralize 19.3 mL of π΅π(ππ»)2. What is the concentration of the π΅π(ππ»)2 solution?
            
            
        Answers
                    Answered by
            DrBob222
            
    2HCOOH + Ba(OH)2 ==> Ba(OOCH)2 + 2H2O
mols HCOOH = M x L = ?
Looking at the balanced equation,mols Ba(OH)2 is 1/2 mols HCOOH.\
Then M Ba(OH)2 = mols BaOH)2/L Ba(OH)2 = ?
    
mols HCOOH = M x L = ?
Looking at the balanced equation,mols Ba(OH)2 is 1/2 mols HCOOH.\
Then M Ba(OH)2 = mols BaOH)2/L Ba(OH)2 = ?
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.