Asked by jay
How long does a ball stay in the air if it is 20m/s and it is thrown straightup?
Answers
Answered by
henry2,
V = Vo + g*Tr = 0
20 + (-9.8)Tr = 0
Tr = 2.04 s. = Rise time.
Tf = Tr = 2.04 s. = Fall time.
T = Tr+Tf = 2.04 + 2.04 = 4.08 s. = Time in air.
20 + (-9.8)Tr = 0
Tr = 2.04 s. = Rise time.
Tf = Tr = 2.04 s. = Fall time.
T = Tr+Tf = 2.04 + 2.04 = 4.08 s. = Time in air.
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