Use formula: F = Gm1m2/d^2
G = 6.67x 10^-11
d = 255 cm = 2.55m (get same unit)
m1 = m
m2 = 3m
2.80 x 10^-12 N = m x 3m / 2.55^2 m
And solve for m
Two spherical balls are placed so their centers are 255 cm apart. The force between the two balls is 2.80 x 10^-12 N. What is the mass of each ball if one ball is 3.00 kg more than the mass of the other ball?
5 answers
d = 2.55 meters
M1 = m kg
M2 = ( m+3 ) kg
G = 6.67 *10^-11
F = G M1 M2 / d^2
2.88 * 10^-12 = 6.67*10^-11 * m (m+3) / 2.55^2
18.7 * 10^-12 = 6.67 *10^-11 (m^2 + 3 m)
m^2 + 3 m = 2.81 * 10^-1 = 0.281
m^2 + 3 m -0.281 = 0
solve quadratic
.0909 = m
3.0909 = m+3
M1 = m kg
M2 = ( m+3 ) kg
G = 6.67 *10^-11
F = G M1 M2 / d^2
2.88 * 10^-12 = 6.67*10^-11 * m (m+3) / 2.55^2
18.7 * 10^-12 = 6.67 *10^-11 (m^2 + 3 m)
m^2 + 3 m = 2.81 * 10^-1 = 0.281
m^2 + 3 m -0.281 = 0
solve quadratic
.0909 = m
3.0909 = m+3
3 more not times random
slight adjustment...
random made one mass three TIMES the other, instead of 3 kg greater
adjust the m2 value and you're good to go
random made one mass three TIMES the other, instead of 3 kg greater
adjust the m2 value and you're good to go
lol, my bad. Sorry