Question

A solution prepared by dissolving 25.8 mg of benzene (78.11 g/mol) in hexane (86.16 g/mol) and diluting to 250 mL had an absorption peak at 256 nm and an absorbance of 0.266 in a 1.000-cm cell.

Question: What is the concentration of benzene solution?
Question: What is the percent transmittance?
Question: What is the molar absorptivity coefficient of benzene?

Answer 1

1. (benzene) = mols/L = (0.0258/78.11)/0.250 = ?
2. log A = log 1/T or 100/%T
3. A = abc
0.266 = a*1*c from 1 above. Substitute and solve for a

Answer 2

I get the 1 and 3, but in number 2. what is T = Po/P before passing and after passing, so what is the T? is it the 256nm and 0.266?

Answer 3

Nvm i already got it, 0.266=-logT derive, 10 raise to -0.266 thanks.

Answer 4

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