Asked by JordanPeara
A solution was made by dissolving 13.4 g of hydrated copper nitrate [Cu(NO3)2.3H20] in water and making it up to a volume of 250 mL. What is the concentration of NO3^-ions in the solution?
Answers
Answered by
DrBob222
mol Cu(NO3)2.3H2O = grams/molar mass = ?
M = mols/L = ?mols/0.250 = ?
Then M NO3^- = twice that.
M = mols/L = ?mols/0.250 = ?
Then M NO3^- = twice that.
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