Asked by vijay parmar
A bus traveling at +30 km/hr accelerates at a constant +3.5 m/s2 for 6.8 s. What is its final velocity in km/hr?
Answers
Answered by
oobleck
3.5 m/s^2 * 1km/1000m * (1hr/3600s)^2 = 12.6 km/hr/s
so, v = 30km/hr + 12.6km/hr/s * 6.8s= 30.238 115.68 km/hr
or, since 30 km/hr = 8.33 m/s,
8.33 + 3.5*6.8 = 33.13 m/s = 115.668 km/hr
so, v = 30km/hr + 12.6km/hr/s * 6.8s= 30.238 115.68 km/hr
or, since 30 km/hr = 8.33 m/s,
8.33 + 3.5*6.8 = 33.13 m/s = 115.668 km/hr
Answered by
henry2,
Vo = 30km/h = 30,000m/3600s = 8.33 m/s.
V = Vo + a*T = 8.33 + 3.5*6.8 = 32.1 m/s.
V = 32.1m/s = 0.0321*3600 = 115.7 km/h.
V = Vo + a*T = 8.33 + 3.5*6.8 = 32.1 m/s.
V = 32.1m/s = 0.0321*3600 = 115.7 km/h.
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