Asked by ben202
What volume of 0.400 M HCl solution is needed to neutralize 30.0 ml of a 0.200 molar solution of KOH?
Answers
Answered by
DrBob222
HCl + KOH ==> KCl + H2O
How many mols KOH? That's M x L = 0.200 x 0.030 = ?
The equation tells you 1 mol HCl needs 1 mol KOH; therefore, mols HCl = mols KOH.
Then mols KOH = M x L. You know M and mols, solve for L needed.
How many mols KOH? That's M x L = 0.200 x 0.030 = ?
The equation tells you 1 mol HCl needs 1 mol KOH; therefore, mols HCl = mols KOH.
Then mols KOH = M x L. You know M and mols, solve for L needed.