Asked by Cole
Find the volume of a 2.5 M solution of sulfuric acid required to prepare 300.0 mL of 0.1 N solution of sulfuric acid
Answers
Answered by
DrBob222
M = (1/2)*N = 1/2 * 0.1 = 0.05
mL1 x M1 = mL2 x M2
mL2 x 2.5 = 300*0.05
mL1 x M1 = mL2 x M2
mL2 x 2.5 = 300*0.05
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