Asked by Hercules
If 32g of kerosine of density of 0.80g/centimeter cube are mixed with 8g of water. What is the density of the resulting vector
Answers
Answered by
oobleck
density = total mass / total volume
(32+8)g / (32/0.8 + 8)cm^3 = 40/48 = 5/6 g/cm^3
vector?
(32+8)g / (32/0.8 + 8)cm^3 = 40/48 = 5/6 g/cm^3
vector?
Answered by
Boateng
Density is =total/mass/total/volume (32+8)g(32/0.8+8)cm^3=40/48=5/6glcm^3
Answered by
Adewumi
Density(Pm)= Mm/Vm
Mm= Mk + Mw
=32 + 8
= 40
Pk= Mk/Vk
Vk= Mk/Pk
=32/0.8
=40cm^3
Vw= Mw/Pw
= 8/1.0
=8cm^3
Mm= Mk + Mw
=32 + 8
= 40
Pk= Mk/Vk
Vk= Mk/Pk
=32/0.8
=40cm^3
Vw= Mw/Pw
= 8/1.0
=8cm^3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.