Asked by DIBIAEZUE CLINTON

If 32 g of kerosene of density 0.80 g/cm^3 are mixed with 8 g of water. What is the density of the resulting mixture
Answered by Damon
volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
Answered by Ebrima Jobe
How did you got the 48
Answered by Covenant
I don't know how he got 48
Answered by Covenant
Please 🙏 solve this question
Answered by Anonymous
volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
Answered by Precious
Is that the final answer
Answered by Hammed
Answer
Answered by Rhema
I don't really understand all this signs as it is written in this google so please make it easy for the audience GOD BLESS YOU
Answered by Rhema
How did you get 48 as the answer