Asked by jake
Jon begins jogging at a steady rate of 3 meters per second from the left side of lane 1. Laura also starts
at the left side, but jogs at a rate of 4 meters per second in lane 2. Ellis starts at the right side of lane 4,
100 meters down the track, and runs towards Jon and Laura at the rate of 6 meters per second. After t
seconds, Jon, Laura, and Ellis all lie in a straight line. Compute t.
at the left side, but jogs at a rate of 4 meters per second in lane 2. Ellis starts at the right side of lane 4,
100 meters down the track, and runs towards Jon and Laura at the rate of 6 meters per second. After t
seconds, Jon, Laura, and Ellis all lie in a straight line. Compute t.
Answers
Answered by
oobleck
With the left and at x=0, after t seconds,
Jon is at 3t
Laura is at 4t
Ellis is at 100-6t
If the lane width is w, then using similar triangles,
(4t-3t)/w = (100-6t - 4t)/2w
2t = 100-6t
t = 12.5
Jon is at 3t
Laura is at 4t
Ellis is at 100-6t
If the lane width is w, then using similar triangles,
(4t-3t)/w = (100-6t - 4t)/2w
2t = 100-6t
t = 12.5
Answered by
jake
hello, thanks for the response
i found out that the way to solve the problem was pretty simple
collinear points all have the same slope, so when u solve for the slope of the positions of Jon, Laura, and Ellis, you'll get:
m = 1 / t (slope b/t Jon and Laura)
m = 2 / 100 - 10t (slope b/t Laura and Ellis)
and you set them equal to each other since collinear points have the same slope, and you'll get t = 8.3
i found out that the way to solve the problem was pretty simple
collinear points all have the same slope, so when u solve for the slope of the positions of Jon, Laura, and Ellis, you'll get:
m = 1 / t (slope b/t Jon and Laura)
m = 2 / 100 - 10t (slope b/t Laura and Ellis)
and you set them equal to each other since collinear points have the same slope, and you'll get t = 8.3
Answered by
oobleck
Ah. I see you used 10 m/s for Ellis, whereas I read the problem and used 6 m/s.
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