Asked by Wendy A.
A person is jogging at 3.5 m/s and grabs a rope that is hanging vertically from a tree. How high can the student swing?
Answers
Answered by
drwls
He can swing upwards a vertical distance H, such that
M*g*H = M*V^2/2
H = V^2/(2g)
H = 1.25 meters
M*g*H = M*V^2/2
H = V^2/(2g)
H = 1.25 meters
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