Asked by Helen

Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them.

How many $9$'s do I have to add before the expected value is at least $8$?
Answered by Damon
$10$ slips of paper

How many ???????
Answered by Damon
Oh , it must be 10
8 = [8*3 + 9*2 + 9*n ] /(10 + n)

80 + 8 n = 24 + 18 + 9 n
n = 80 - 24 - 18
Answered by himani
The answer isn't 10. It is 80 - 24 - 18 = 38.
Answered by GHASTLY
I think that is what Damon meant. I think Damon was just wondering what $10$ meant.
Answered by {Unavailable}
Is this copied from AoPS? I can see the exact same question there. If you need help you shouldn't come here.
Answered by 1212
Bruh this is AOPS
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