Question
A force of 25 N is needed to move automobile wheels up a smooth incline
10 m along in an automotive plant.
a. If each of the wheels weighs 125 N what work is done on each?
b. How high above the floor is the top of the incline?
10 m along in an automotive plant.
a. If each of the wheels weighs 125 N what work is done on each?
b. How high above the floor is the top of the incline?
Answers
henry2,
a. W = F*d = 25 * 10 = 250 J.
b. Fp = 125*sinA = 25 = Force parallel with incline.
sinA = 25/125 = 0.20, A = 11.5o.
sin11.5 = h/10
h = 10*sin11.5 =
b. Fp = 125*sinA = 25 = Force parallel with incline.
sinA = 25/125 = 0.20, A = 11.5o.
sin11.5 = h/10
h = 10*sin11.5 =