Asked by George
I need some help with my radical equations. I would really appreciate some aassistance.
Answers
Answered by
Damon
Please post an example of what you are having trouble with and your attempt to solve it.
By the way when you do, please write square root of x as sqrt(x)
and a cube root or fourth root as x^(1/3) or x^(1/4). hen we will undertand what you mean.
By the way when you do, please write square root of x as sqrt(x)
and a cube root or fourth root as x^(1/3) or x^(1/4). hen we will undertand what you mean.
Answered by
Mike
. 3/[SQRT(5) - 2]
Simplify.
Simplify.
Answered by
Damon
multiply top and bottom by (sqrt(5) + 2 )
.3 [sqrt(5)+2]/ {[ sqrt (5) -2][sqrt(5) +2] }
= (.3 sqrt(5) +.6)/ (5-4)
= .3 sqrt(5) + .6
.3 [sqrt(5)+2]/ {[ sqrt (5) -2][sqrt(5) +2] }
= (.3 sqrt(5) +.6)/ (5-4)
= .3 sqrt(5) + .6
Answered by
Mike
Can you do the same with this?
3b[SQRT(27a5b)] + 2a[SQRT(3a3b3)]
3b[SQRT(27a5b)] + 2a[SQRT(3a3b3)]
Answered by
Mike
3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
Answered by
Damon
3 b sqrt ( 3*9 a a^4 b) + 2a sqrt (3 a a^2 b b^2)
3 b 3 a^2 sqrt(3 a b) + 2 a a b sqrt(3 a b)
9 a^2 b sqrt (3 a b) + 2 a^2 b sqrt (3 a b)
11 a^2 b sqrt (3 a b)
3 b 3 a^2 sqrt(3 a b) + 2 a a b sqrt(3 a b)
9 a^2 b sqrt (3 a b) + 2 a^2 b sqrt (3 a b)
11 a^2 b sqrt (3 a b)
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