What is the Ksp of Lead II Fluoride if the lead and fluoride ions have molecular concentrations of 4.8 x 10-4 M and 8.7 x 10-3 M respectively in a saturated solution at 25oC?

Question

Please show work. I don't even know where to start.

Answer 1

.............PbF2 ==> Pb^2+ + 2F^-
I..............solid.........0.............0
C............solid..........x.............2x
E............solid..........x.............2x

Ksp = (Pb^2+)(F^-)^2
The problem tells you the value of x and 2x. Substitute those into the Ksp expression and solve.

Answer 2

@DrBob222 Thank you Sir