Asked by Jane
The concentration of fluoride ions in a saturated solution of barium fluoride is __________ M. The solubility product constant of BaF2 is ???
Answers
Answered by
Jane
The solubility product constant of BaF2 is 1.7 x 10^-6 forgot to put that
Answered by
bobpursley
ksp= (ba)(F)^2= x*(2x)^2
x= cubrt(ksp/4)
x= cubrt(ksp/4)
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