Asked by hewwo :)

The sample space for a roll of two number cubes is shown in the table
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
The two numbers rolled can be added to get a sum. Find P(sum is greater than 5).
A) 5/6
B)13/18
C)5/18
D)1/3

I don't understand how to solve this question please help!
Answered by oobleck
How many sums are greater than 5?
6 can happen in 5 ways: (1,5),(2,4),(3,3),(4,2),(5,1)
Count the ways for 7,8,9,10,11,12
P(sum > 5) is (#ways to get a sum > 5)/36
Answered by hewwo :)
okay thanks that makes a ton of sense :)
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